(6y^1/4)^3/y^1/12

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Solution for (6y^1/4)^3/y^1/12 equation: 


D( y )

y^1 = 0

y^1 = 0

y^1 = 0

y = 0

y in (-oo:0) U (0:+oo)

((((6*y^1)/4)^3)/(y^1))/12 = 0

((((6*y)/4)^3)/y)/12 = 0

9/32*y^2 = 0 // : 9/32

y^2 = 0

y = 0

y in { 0} 

y belongs to the empty set

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